Python: Getting next available number
# Getting next available number. def getFollowingNumber(inArgs): ret= False; current= inArgs[0]; array= inArgs[1]; num= len(array); for i in range(0, num): if array[i]==current: k= current; j= i; for j in range(j, num): if k!=array[j]: ret= k; break; k+=1; break; if not ret: ret= current; return(ret); current_number= 8; # Change this number numberList= [0,1,2,3,4,5,8,9,10,11,12,16,17,19,20,21,23,24,25,26,28,29,31]; new_number= getFollowingNumber...